(5x=3x+8)-(2x^2+4x-2)

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Solution for (5x=3x+8)-(2x^2+4x-2) equation: 



(5x=3x+8)-(2x^2+4x-2)

We move all terms to the left:

(5x-(3x+8)-(2x^2+4x-2))=0



We calculate terms in parentheses: +(5x-(3x+8)-(2x^2+4x-2)), so:

5x-(3x+8)-(2x^2+4x-2)

We get rid of parentheses

-2x^2+5x-3x-4x-8+2

We add all the numbers together, and all the variables

-2x^2-2x-6

Back to the equation:

+(-2x^2-2x-6)



We get rid of parentheses

-2x^2-2x-6=0

a = -2; b = -2; c = -6;
Δ = b2-4ac
Δ = -22-4·(-2)·(-6)
Δ = -44
Delta is less than zero, so there is no solution for the equation

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